You'reRidingAnElevatorHoldingASpringScaleW/A1kgMassSuspendedFromIt.ThenScaleReads9.3N.WhatIsAccelerationOnElevator?

Question

Physics Question 

Answer 1

If the elevator were standing still, the spring would have indicated a weight of mg =1kg x 9.8 m/s^2 = 9.8 N.

If the elevator were moving up with acceleration A, the spring would have indicated a weight of m(g+A),

and if accelerating down, m(g-A).

Substituting, 1 x (9.8-A) = 9.3            A = 0.5 m/s^2 downward

Answer 2

F=ma

 

9.3N=1kg*a

 

a=9.3m/s²