400 g of steem at 400c is cooled to ice at 0c. howmany joules of heat must be lost to achive this change

Question

400 g of steem at 400c is cooled to ice at 0c. howmany joules of heat must be lost to achive this change

Answer 1

The heat lost consists of 4 parts:

 

1. Heat released as the steam cools from 400°C to 100°C: Q₁=m c_steamΔT

2. Latent heat of vaporization, as the steam condenses at 100°C: Q₂=m L_v

3. Heat released as the water cools from 100°C to 0°C: Q₃=m c_waterΔT

4. Latent heat of fusion, as the water freezes at 0°C: Q₄=m L_F

 

Look up the constants, c_steam, c_water, L_v, and L_f, calculate Q₁ through Q₄, then add them! Enjoy! :)