What mass of PCl5 will be produced from the given masses of both reactants?**Part D is what I need help on**

Question

Calculations involving a limiting reactant
Now consider a situation in which 26.0 g of P4 is added to 59.0 g of Cl2, and a chemical reaction occurs. To identify the limiting reactant, you will need to perform two separate calculations:
Calculate the number of moles of PCl5 that can be produced from 26.0 g of P4 (and excess Cl2).
Calculate the number of moles of PCl5 that can be produced from 59.0 g of Cl2 (and excess P4).
Then, compare the two values. The reactant that produces the smaller amount of product is the limiting reactant.
Part B
How many moles of PCl5 can be produced from 26.0 g of P4 (and excess Cl2)?
Express your answer to three significant figures and include the appropriate units.
0.839 mole....answer to B


Part C
How many moles of PCl5 can be produced from 59.0 g of Cl2 (and excess P4)?
Express your answer to three significant figures and include the appropriate units.
0.333 mole.....answer to C


Part D
What mass of PCl5 will be produced from the given masses of both reactants?
Express your answer to three significant figures and include the appropriate units.

****this is what I need help on***

Thank you!

 

Answer 1

First, set up your equation and balance it. Then, from parts B and C, you know which reagent is the limiting reagent. Knowing which reagent is limiting, you calculate the theoretical yield of this reaction based on that reagent and ignoring the other one.