Dona,
The intuitive way to find the limit is to expand sin(x) in a power series around 0, i.e. sin(x)≈x-x3+x5/120+.....for x near 0.
so sin(x)/x≈1-x2+x4/120+.... we can now take the limit limx→0sin(x)/x=1. QED :)
Hope this helps
Jim