Find the counterexample to disprove the conjecture

Question

the value of X3(cube) is always greater than the value of x

Answer 1

Conjecture:  x³>x for all values of x.

 

Counterexample:  When x = ½

 

        (½)³ = 1/8, which is not greater than ½

Answer 2

x³ > x

 

 

The counterexample.  If x is less than or equal to 1, and is a constant value.

 

(-x)³ > -x        ,         0³ > 0         ,             1³ > 1

 

-x > -x            ,         0 > 0         ,              1 > 1

 

 

The above statements are not true.