William had $45 dollars to spend on vegetables. After buying 6 watermelons, he had $25.50 left. How much did each watermelon cost?

Question

I need help with math.William had $45 dollars to spend on vegetables. After buying 6 watermelons, he had $25.50 left. How much did each watermelon cost? HELP!!!

Answer 1

William had $45 & bought 6 watermelons which left him with $25.50.  So, $45-&25.50=$19.50. Divide $19.50 by 6=$3.25=for each watermelon.

Answer 2

For this problem, let's use w for watermelons since that is the unknown.

You know that you have $45.00 to spend and that after buying 6 watermelons, you have $25.50 left. This means that you would have spent $19.50 dollars on the 6 watermelons ( $45.00- $25.50= $19.50). From here, you would divide the money spent by the amount of watermelons bought so you would isolate w.

 

If you need to see the algebraic equation to visualize it, think about how you ended up with $25.50 but started with $45.00. The purchase of watermelons would decrease what you have left, so subtraction is involved between the purchase and the starting amount, therefore the equation would be: 45-6w=25.50.

 

Solve for w by isolating it from the numbers [hint: moving the numbers would give you -19.50 since the equation would become -6w= -19.50]!

Answer 3

Let w = the price of a watermelon. He bought 6 of them, so he spent 6w dollars on watermelons.  What he had left was this subtracted from 45, giving us   45 - 6w.

 

Since we know that he had 25.50 left, we have the equation  45 - 6w = 25.50. I'm sure you know how to solve this from here.

 

If not, you subtract 45 from each side, giving   -6w = -19.50

 

Then divide both sides by -6, telling us that w = $3.25 for each watermelon.