Inactive Tutor answered 10/22/15
Tutor
New to Wyzant
We can factor 9-x on the bottom as (3-√x)(3+√x).
Then we can cancel out the 3-√x s. We are left with 1/(3+√x). Now if we plug in 9 for x. We get a value of 1/6, so it is continuous at x=9.