Can you help me with this volumetric stoichiometry problem?

Question

How many grams of chlorine has would be produced is 250 mL of 2.00M HCl was mixed with an excess of bleach, according to the equation below? 

 

NaClO (aq) + HCl (aq) => Cl2 (g) + NaOH (aq)

 

Can you please show your steps? I don't know how to solve this and would love to learn!

Answer 1

Here is the thought process that I used to solve this question:

 

NaClO (aq) + HCl (aq) => Cl₂ (g) + NaOH (aq)

                     250 mL HCl                  ? g

                     2.00 M HCl

 

1) Use the Molarity of HCl given and the volume to find the number of moles of HCl in the reaction

 

250 mL--->.250L *(2.00 mol/1L)=0.5 mol HCl

 

2) Determine how many molar equivalents of Cl₂ are produced

 

0.5 mol HCl *(1 mol Cl₂/1 mol HCl)= 0.5 mol Cl₂

 

3) Use the molecular weight of Cl₂ to determine the mass of chlorine formed

 

0.5 mol Cl₂ *(35.453 g/ 1 mol Cl₂)= 17.7265 g Cl₂ produced

 

I hope this was helpful!

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