
Abouzar G. answered 10/05/15
Tutor
New to Wyzant
PhD - Teaching Mathematics conceptually for the best grades
In 6 gallons of 50% acid, we have: 3 gallons acid, and 3 gallons water.
Let x denote the pure acid amount to add to the solution to get 70% acid. We have:
(3 + x)/(6 + x) = 70/100, so we have: 100 * (3 + x) = 70 * (6 + x). Solving this equation, we have: x = 4 gallons.
Let x denote the pure acid amount to add to the solution to get 70% acid. We have:
(3 + x)/(6 + x) = 70/100, so we have: 100 * (3 + x) = 70 * (6 + x). Solving this equation, we have: x = 4 gallons.