He paid $6.60 per case for one brand and $7.20 per! case for the other brand. If the total cost was $273.00 for 40 c

Question

A grocer bought two brands of frozen juice. He paid $6.60 per case for one brand and $7.20 per! case for the other brand. If the total cost was $273.00 for 40 cases, how many cases at $6.60 did he buy?

Answer 1

Ben,

 

As always, there is more than one way to solve a problem like this. Here's one approach.

 

Assign variable names: juice brand #1 = a, juice brand #2 = b

 

Price for the different brands: $6.60 per case of brand a, $7.20 per case for brand b.

 

Total # of cases of each brand: a + b = 40

Total cost for 40 cases: $6.60a + $7.20b = $273.00

 

We have to solve for a.

 

Since a + b = 40, then b = 40 - a, so we can substitute this term for b

 

6.6a + 7.2b = 273

 

6.6a + 7.2(40 - a) = 273

 

6.6a + 288 - 7.2a = 273

 

6.6a - 7.2a + 273 - 288

 

-0.6a = -15

 

a = 25 cases of the $6.60 juice brand

 

 

I hope this helps!

 

Neal