How many possible groups?

Question

If there is 11 people and need groups of 5 how many different possibilities are there? And how do you find this answer?

Answer 1

You would find a combination with C(11,5), where C(n,k) = n! / (k!*(n-k)!)

 

C(11,5) is:

 

11! / (5! * 6!)

 

(Remember that:)

11! = 11*10*9*8*7*6*5*4*3*2*1

5! = 5*4*3*2*1

6! = 6*5*4*3*2*1

 

C(11,5) =

11*10*9*8*7*6*5*4*3*2*1

(5*4*3*2*1) (6*5*4*3*2*1)

 

= 11*10*9*8*7

   5*4*3*2*1

 

= (11*9*8*7)/(4*3) = 462 possible combinations!