in how many ways can two republicans, one democrat, and oneindependent be chosen from amoung nine republicans, five democrates, and two independent

Question

Algebra 2 help. Struggle a lot with algebra. could use the help asap.

Answer 1

you can set this up as:

 

there are are four spots to be filled: _,_,_,_ 

Remember, since order the way the republicans are chosen does not matter, (combination), choosing 2 republicans from 9 is given by

(9!)/(9-2)!2!=360

 

To calculate all possible ways you will multiply all these numbers

1. There are nine possible republicans, so (9!)/(9-2)!2!=36
2. There are five possible democrats, so 5,
3. And 2 independent candidates.

The answer will be,

(36)(5)(2)=360

 

There are 360 ways

 

Answer 2

360 combinations:

 

You can have 36 combinations of Republicans, 5 Democrats, and 2 Independents

 

Therefore: 36 * 5 *2 = 360