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one point which must be on the graph of each of the following functions.

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1 Answer

We have g(7)=4.
 
Define f1(x) =1/4 g(x). Then f1(7)=1/4 g(7) =1, so (7,1) is on the graph of f1.
 
Define f2(x) = g(1/4 x). Then f2(28)= g(7) =4, so (28,4) is on the graph of f2.
 
Define f3(x) =-g(4x). Then f3(7/4)= -g(7) =-4, so (7/4,-4) is on the graph of f3.
 
Define f4(x) =-4 g(x). Then f4(7)=-4 g(7) =-16, so (7,-16) is on the graph of f4.