We have g(7)=4.
Define f_{1}(x) =1/4 g(x). Then f_{1}(7)=1/4 g(7) =1, so (7,1) is on the graph of f_{1}.
Define f_{2}(x) = g(1/4 x). Then f_{2}(28)= g(7) =4, so (28,4) is on the graph of f_{2}.
Define f_{3}(x) =g(4x). Then f_{3}(7/4)= g(7) =4, so (7/4,4) is on the graph of f_{3}.
Define f_{4}(x) =4 g(x). Then f_{4}(7)=4 g(7) =16, so (7,16) is on the graph of f_{4}.
9/24/2013

Andre W.