Roman C. answered 09/29/15
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Masters of Education Graduate with Mathematics Expertise
Note that if a function f(x) is period p, then
af(x) still has period p for a≠0 because you are just rescaling the values of the function, and
f(ax) has period p/a because the value of f(x) at x = k is the same as that of f(x) at x = k/a, so the graph is scaled by a factor 1/a along the horizontal direction.
Since {x} has period 1, we therefore find that a{x} still has period 1 but {ax} has period 1/a