
Mark M. answered 09/27/15
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Mathematics Teacher - NCLB Highly Qualified
A = a0(0.5)t/h, where a0 = original amount, t = time, h = half-life, A = current amount
3.0 x 10-3 = a0(0.5)4/10.2
0.003 ≈ a0(0.5)0.392156863
0.003 ≈ a0(0.761989560)
0.00393706181 ≈ a0
The concentration was approximately 3.9 x 10-3 M