Let x = number of $1 decreases in price
Revenue = R(x) = (price)(quantity)
= (18 - x)(1500 + 100x)
The graph of R(x) is a parabola opening downward. The graph has x-intercepts when 18-x = 0 and when 1500 + 100x = 0.
So, the x-intercepts are 18 and -15.
By the symmetry of the graph, the highest point of the graph lies halfway between the x-intercepts (x = (18 + (-15))/2 = 3/2 = 1.5)
Maximum revenue = R(1.5) = (16.5)(1650) = $27,225
If the ticket price is $16.50, the revenue will be maximized.