word problem help!

Question

sharyn invests $2000 more in an account that earns 9% simple interest than she invests in an account that earns 6% simple interest. How much did she invest in each account if her total interest is $405 after 1 year?

Answer 1

Let amount invested in 6% account = X

So amount invested in 9% account = X + 2000

 

Interest earned by 6% account = X x 6/100 x 1 = 6x /100

Interest earned by 9% account = (X+2000) x 9/100 x 1 = 9x/100 + 180

 

as per question

 

6x/100 + 9x/100 + 180 = 405

 

solve for x

 

15x/100 = 225

 

x = 1500 = amount invested in 6 % account

 

amount invested in 9% account - 1500 + 2000 = 3500