
Thomas E. answered 09/15/15
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Tom E., a Patient and Knowledgeable Mathematics Tutor for You
This is a variation on the standard rate/distance/time problem (D=R*T). The distance in both directions is the same, the time is as noted in the problem, and the rate is different in each direction because of the current. Let R=the speed of the boat. Upstream the rate will be R-3, and the downstream rate is R+3. Since the distance is the same we can write the equation as this:
(R-3)*5 = (R+3)*2.5 Solve this algebraically
5R-15 = 2.5R + 7.5
2.5R = 22.5
R = 9