For velocity yes you need one derivative to find a formula for velocity and another one to get the maximum.
Shirin Z.
tutor
ok I will do the velocity
V=dx/dt=2At-3Bt^2
now if dV/dt=0 that is a maximum
so
dV/dt =2A-6bt=0 => t=A/3B
so maximum is 2A(A/3B)-3B(A/3B)^2=(A^2)/3B
do not look at the second derivative as acceleration. It is just a derivative that if it is equal to zero will give you the maximum of the curve (in this case Velocity).
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09/02/16
Megan L.
09/02/16