Roman C. answered 09/06/15
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[1/(x+h)2 - 1/x2] / h
= { x2/[x2(x+h)]2 - (x+h)2/[x2(x+h)2] } / h
= [x2 - (x+h)2] / [hx2(x+h)2]
= [x2 - (x2+2hx+h2)] / [hx2(x+h)2]
= -h(2x+h) / [hx2(x+h)2]
= (-2x-h) / [x2(x+h)2]
= (-2x-h) / [x2(x2+2hx+h2)]
= (-2x-h) / (x4+2hx3+h2x2) ← Simplified Expression
The meaning of this expression is the average rate of change of the function f(x) = 1/x2 in the interval [x,x+h].
The limit h→0 is easier to compute, since you can just plug in h=0. Such a limit is it's instantaneous rate of change or the derivative, d/dx 1/x2 which is (-2x-0)/(x4+2·0x3+02x2) = -2/x3.
L R.
09/06/15