Chemistry Question 3 Need Help ASAP

Question

A laboratory experiment requires 2.0 L of a 1.5 M solution of hydrochloric acid (HCl), but the only available HCl is a 12.0 M stock solution. How could you prepare the solution needed for the lab experiment? show all work used to find the answer

Answer 1

The dilution equation is helpful here.    It is:

 

  M₁V₁  =  M₂V₂    

 

where the M_i  are the molar strengths of the two solutions and  V_i  are the volumes.

 

  For the problem at hand  V₂ =  2,   M₂ =  1.5 and M₁ = 12.  Plugging in one gets   V₁ = 0.25 L

 

  This means that one must add 0.25L of the 12M stock to 1.75 L of distilled water to make up the desired 2 L.

 

To do this safely, decant  0.25 L of the stock solution to a suitably sized beaker.  Pour this carefully into a vessel containing 1.75 L distilled water.