The perimeter of a rectangular playing field is 432 yards. The length of the field is 8 yards less than triple the width.

Question

What are the dimensions of the playing feild

Answer 1

P=2l+2w

P=2(3w-8)+2(w)

432=2(3w-8)+2(w)

432=6w-16+2w

432=8w-16

432+16=8w

448=8w

w=448/8

w=56yards

 

 

l=3(56)-8

l=168-8=160yards