What is the slope of the line parallel to the line whose equation is given by -y=-4x+6

Question

this honestly has my mind boggled. I haven't been in school for 3 years and I am completely lost. I need an explanation of how to work this problem out or as much as you can tell me. thank you.

Answer 1

-y = -4x + 6               multiply both sides by -1

y = 4x - 6                   this is slope intercept form, y = mx + b, where m = the slope

 

The slope of this line is 4/1 and all parallel lines shall have the same slope, 4/1.

Answer 2

The handy thing about slope-intercept form for the equation of a line (y=mx + b) is that parallel lines have the same slope.
All lines parallel to this line have slope m=4.  That means (considering slope as "rise over run," that the y value increases by 4 for each increase in 1 for x;  this is a really steep hill to climb).
 
All perpendicular lines have a slope that is the negative reciprocal (that is, -1/m), so their equations are of the form:  

  y=(-1/m)x+ d  (where b and d are the y-intercepts, the place where the line crosses the y-axis; that is, the value of y when x=0).