
Shradha S. answered 08/18/15
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Experienced Maths Teacher with Master's Degree in Mathematics
dy/dx=(x+1)/y2
applying variable separable method
y2 dy =(x+1) dx
Integrating above we will get...
y3 /3 = x2/2 + x + C
y3 = (3/2)x2 + 3x +3C (As it passes through the point (-2, 2) put x=-2 and y=2
23 = (3/2)*(-2)2 +3*(-2) +C' ;replacing 3C with another constant C'
8 = +6 -6 +C'
8 =C'
So y3 = (3/2)x2 + 3x +C'
y3 =(3/2)x2 + 3x + 8
y = 3√(3/2 x2+3x+8) and this your ans...