Mark M. answered 08/18/15
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
N(t) = amount remaining in t years = N0e-kt
Since N(32) = N0/2, we have N0/2 = N0e-32k
Divide by N0: 1/2 = e-32k
Take natural logs: ln(1/2) = -32k
k = ln(1/2)/(-32) ≈ 0.0217
N(t) = N0e-0.0217t [Answer (c)]