SURENDRA K. answered 08/16/15
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The total interval is divided into 5 subintervals of width 1 each
The five ordinates are corresponding to x=0,1,2,3,4
Corresponding y ordinate =0,1,4,9,16
Integral = o*1+1*1+4*1+9*1+16*1
=30
Using right hand approximation--------
x=1,2,3,4,5
y=1,4,9,16,25
Integral =1*1+4*1+9*1+16*1+25*1
=55
Using mid point approximation -----------
x=0.5,1.5,2.5,3.5,4.5
y=0.25,2.25,6.25,12.25,20.25
Integral =0.25*1+2.25*1+6.25*1+12.25*1+20.25*1
=41.25
Answer b is correct