Rasika R.
asked 08/16/15need answer using bar model if possible
David and Joseph have a total of 328 marbles. Mathew and David have 176 marbles. Joseph has 5 times as many marbles as Mathew.How many marbles does David have? need answer using bar model if possible
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2 Answers By Expert Tutors

Shradha S. answered 08/16/15
Tutor
4
(1)
Experienced Maths Teacher with Master's Degree in Mathematics
I cant draw a proper bar but I can give you an idea to solve using bar method.see David is commomn ,so I am going to put David first
[_David_] [_Mathew_] = 176
[_David_] [________Joseph_____________] = 328
Its given that Joseph has 5 times as many marbles as Mathew.So we can divideJoseph's bar into 5 equal parts where each part represents Mathew's no.of marbels
[ David_][_Ma_][_Ma_][_Ma_][_Ma_][_Ma_] = 328 ;but David and Mathew has total 176 mrbl
{ 178 }{ 4 times mathews marbels}
328-176 =152
there fore Mathews has 152/4 = 38 marbels and so from first set of bars
[_David_] [_Mathew_] = 176
David + 38 = 176
David = 176 -38 = 138
Michael J. answered 08/16/15
Tutor
5
(5)
Applying SImple Math to Everyday Life Activities
Let D = number of marbles David has
Let J = number of marbles Joseph has
Let M = number of marbles Mathew has
We can write equations using these variables to help us solve the problem.
D + J = 328 eq1
D + M = 176 eq2
J = 5M eq3
We have a system of equations. Since we want to find how many marbles David has, we need to solve for the variable D. However, we have 3 equations with 3 different variables. So we need to use substitution and elimination methods.
First, we can substitute eq3 into eq1. Let's get eq1 in terms of D and M. In the end, we will have one less equation and one less variable to deal with.
D + 5M = 328 eq1
D + M = 176 eq2
We have only two equations as promised.
Next, we can multiply eq2 by 5. Keep eq1 as it is.
D + 5M = 328 eq1
5D + 5M = 880 eq2
Subtract eq2 from eq1 to eliminate the M terms.
-4D = -552
Divide both sides of the equation by -4.
D = 138
David has 138 marbles.
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Michael J.
08/16/15