Elise A.

asked • 08/13/15

9th Grade Math Help (PLEASE Help Me!!)

I need ASAP help on how to just set up these problems... what they mean and all that; I'm not just looking for the answer. The first one goes like this:
 
The equation P=0.00267sF gives the power P (in horsepower) needed to keep a certain bicycle moving at speed s (in miles per hour), where F is the force of road and air resistance (in pounds). On level ground this force is given by F=0.0116s2+0.789. Write a polynomial function (in terms of s only) for the power needed to keep the bicycle moving at speed s on level ground. How much power does a cyclist need to exert to keep the bicycle moving at 10 miles per hour?
What I got was: The power needed to maintain a speed of s is .00267s(.01162+.789), so the power needed to maintain a speed of 10 mph would be .0520383. Is this even close to right??
 
The second one is this:
 
For 1980 through 1995, the number of degrees D (in thousands) earned by people in the United States and the percent of degrees P earned by women can be modeled by
D= -0.096t4+3t3-27t2+91t+1700
P= 0.43t+49
where t is the number of years since 1980. Find a model that represents the number of degrees W (in thousands) earned by women from 1980 to 1995. How many degrees were earned by women in 1991?
I haven't even tried this one yet I'm so confused!!
 
Please, please, PLEASE help me I'm so confused and on the verge of tears because I'm scared that I might get a really bad grade on the quiz tomorrow... please help me I'm begging you I'm so confused right now :(

1 Expert Answer

By:

Shradha S. answered • 08/13/15

Tutor
4 (1)

Experienced Maths Teacher with Master's Degree in Mathematics

Elise A.

Thank you so much for responding quickly! Big thanks for the help :) Also, not to be a bother, but could you look at the second question too? I literally have no idea how to even approach it :(
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08/13/15

Shradha S.

I am not sure but I think total no. of people obtained degree is defined by function D and the percentage of the women obtained degree will be by P.So to get the no of women earned degrees should be defined by the product function of D and P.
i.e.  W = D* P
          = ( -0.096t4+3t3-27t2+91t+1700) * (0.43t+49)
 
and as the no. of years from 1980 to 1995 is 16 .so you need to put t = 16 in the function W. as well as to get the no in year 1995 ,you need to find the no upto 1995 and 1994 and find their difference to get the no. of women obtained degree only in the year 1995.
 
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08/13/15

Shradha S.

sorry, the second part is no. in 1991 not 1995....so find the no. upto 1991(t=12) and 1990(t=11) and find their difference to get the no. of women obtained degree only in the year 1995.
 
I hope it should work
 
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08/13/15

Elise A.

Ok, I'll try that now :) Thanks so much for explaining it to me; I feel so much better now :)
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08/13/15

Elise A.

For my answer I got 108613.26072. Hopefully it's right!! :D
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08/13/15

Shradha S.

All the best for your Quiz..:)
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08/13/15

Elise A.

Thank you again, you're so nice!!
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08/13/15

David W.

The two functions in part 2 are:
     D = number of degrees (total)
     P = percent of degrees earned by women
 
Sometimes, thinking in terms of sample numbers helps to understand how units of measure apply in the problem.  So, if D=200 and D=40, that would read as "there were 200 degrees in a certain year and 40% of them were women," and we know that the word "of" usually means "multiply" and that percent can be written as 40% or 40/100 or 0.40, so we have, for example:
      40% of 200  = (40/100)*200  = 0.40*200        [this is why the formula is PD]
 
The entire second problem is made up.  The important part is "find a model."  That is, write a short, concise, precise math formula.  And, you do that by writing N=PD.  It's that simple.
 
All the problem wants to know is "what is the model?"   So, if someone wrote N=P/D, that would be wrong.  And N=P-D doesn't make sense because it combines percent and degrees (which, like apples and oranges don't add), and ...  You know, sometimes it helps to see all the answers that a teacher sees (if you can help from laughing out loud).
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08/13/15

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