Stephanie M. answered 07/25/15
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In a normal square root, you can factor everything inside the radical and then "take out" factors that occur twice:
√(12y2) = √(2×2×3×y×y) = 2y√(3)
That's because an expression with two of the same factors like √(2×2) = √(22) = 2.
A similar process takes place with cube roots, but this time, we can "take out" factors that occur three times. So:
3√(8g6) = 3√(2×2×2×g×g×g×g×g×g)
There are three 2's and two groups of three g's. So, we'll take out a 2 and two g's. That leaves us with:
2g2