Chem question

Question

What mass of potassium nitrate is produced when 50.0mL of 0.200 M Al(NO₃)₃ reacts with 200.0mL of 0.100 M KOH?

Answer 1

Al(NO₃)₃ + 3KOH -------> 3KNO₃ + Al(OH)₃

 

50 ml * .2 moles/ liter = .01 Moles of Al(NO₃)₃

 

200 ml * .1 moles/liter = .02 Moles of KOH 

 

Since the ratio between the two reactants according to the chemical equation is 1:3, we would need .03 moles of one to fully react with .01 moles of the other. Since we don't, only 1/150 mole of the first reactant will react with the .02 moles of the second reactant. This will produce .02 moles of KNO₃ as well as .01 moles of Al(OH)₃

 

.02 moles KNO₃ = .02(48 grams + 14 grams + 40 grams) = .02(102 grams) = 2.04 grams