Pooja S.

asked • 07/18/15

A watch costs $48 more than a clock.The cost of the clock is 4/7 the cost of the watch.Find the total cost of the two items.

How can this question be expressed & explained in equation?

Pooja S.

Sorry the answer is incorrect. 
 
Here is the solution I found online, but I was wondering how can this be interpreted & solved in form of equation. Following is the online solution:
 
Since we know that 3/7 of the watch is $48 more that the
clock, we can divide 48 by 3 to find the cost of 1/7.
$48 ÷ 3 = $16
Now all we need to do to find the total cost is multiply the
total number of 7ths by the cost of each one, $16. We know that
the watch is 7/7 and the clock is 4/7, so we con multiply $16 by 11
to find the total cost.
$16 x 11 = $176
Answer: __$176__
Report

07/19/15

David W.

Take the "show me" (from Missouri car license plate) approach.  Specifically, let's go to the (very important) answer check portion.
 
C=64 and W=112 checks out.
 
What were the on-line answers?    The clock costs 4*16 = $64 and the watch costs 7*16 = $112, which is $48 more than the cost of clock.  Together, they cost 64 + 112 = $176.   [Hey, the individual costs match my answer.]
 
So (even though I could edit Answers but not Comments), PLZ replace the test starting with "Now, what is the total cost of the two items?"
Now, what is the total cost of the two items?
              $64 + $112 = $176
 
Checking (very important):
    Is 176 = 64 + 112    ?    yes!
 
    Is  64 = (4/7)*112   ?
         64 =  64       yes!
           
(This is crucial -- which is why I left my original answer -- The Checking only verified that the clock cost (4/7) of the cost of the watch and that the sum was the value reported.  But, since the wrong value was reported as the sum, the check passed.   Clearly, if we see C=64 and W=112, the total cost line is a typo.  The sum is $176.
 
THX for noticing this!  Now, work on how to correct wrong answers and you will be a great teacher/tutor someday.
 
(p.s.. I don't know your good Internet source, but at least be wary of them.)
Report

07/19/15

1 Expert Answer

By:

David W. answered • 07/18/15

Tutor
4.7 (90)

Experienced Prof

Pooja S.

Thank you very much.
Report

07/21/15

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