6x2-3x-7 :find the roots

Question

Find THe roots

Answer 1

6x²-3x-7

We want the values of x that make this quadratic equal to zero

 

Use the quadratic equation  for  ax²+bx+c=0   x= -b/2a ± (√(b²-4ac))/2a

For this equation   a=6, b=-3, c = -7

 

x = -(-3)/2(6) ±[√((-3)²-4(6)(-7))]/2(6)

x = 1/4 ±[√(9+168)]/12

x = 1/4 ±(√177)/12