Suppose f(5)=4, f'(5)=5, f(17)=7, f'(17)=-3, and H(x)=f(x^2-8). Find dH/dx||||x=5. H'(5)=?

Question

in desperate need of help

Answer 1

H(x) = f(x² - 8)

 

H'(x) = f'(x² - 8)(x² - 8)'  = f'(x² - 8)(2x)

 

So, H'(5) = f'(17)(10) = (-3)(10) = -30