Well, teaching you all about proportions is not something that can be done in a small space. However, you were on the right track in understanding what the proportions mean -- you just didn't apply them correctly.
You are correct that A is 7/9 gold and B is 7/18 gold. But when you mix them, you don't just add the two fractions together.
There are two ways to look at this problem:
1. When you add EQUAL amounts of two alloys together, then the fraction of the resulting alloy that is gold will be the AVERAGE of the fractions in the original alloys. So you would add 7/9 to 7/18 and then take the average by dividing by 2. So that's (7/9 + 7/18) / 2 = (14/18 + 7/18) / 2 = (21/18) / 2 = (7/6) / 2 = 7/12. So the resulting alloy has 7 parts gold out of 12, so the rest, 5 parts is copper. So the ration is 7:5.
If the amounts of A and B were NOT equal, then you would do something similar, using the concept of WEIGHTED average, but that's not something to go into now.
2. You're mixing the same amount of each alloy together, so let's call that amount x. That means that the amount of gold in the sample of A is 7/9 x and the amount of gold in the sample of B is 7/18 x. When you add the two samples together, you get 21/18 x = 7/6 x. That's the amount of gold you have in the mixture. But the TOTAL amount of metal is actually 2x, since you added x of A and x of B together. So the fraction of the mixture that is gold is (7/6 x) / (2x) = 7/12. You end up with the same answer as before, but from a slightly different point of view.
Amey B.
07/11/15