
David W. answered 07/03/15
Tutor
4.7
(90)
Experienced Prof
Water freezes at 32°F (0°C) and boils at 212*F (100°C).
Thinking of this as a line function F(C), the slope (rise over run) is (212-32)/100 = 180/100 = 9/5. The value of F(0) [when C=0 ] is F=32 (the F-intercept is like the y-intercept). In the form y=mx + b, this is °F = (9/5)°C + 32°.
Practice solving this formula for C to go the other way.
For this problem: F = (9/5)*50 + 32 = 122°
Checking:
To convert from °F back to °C, use C=(5/9)(F-32)
C = (5/9)(122-32) = (5/9)(90) = 50°C
Thinking of this as a line function F(C), the slope (rise over run) is (212-32)/100 = 180/100 = 9/5. The value of F(0) [when C=0 ] is F=32 (the F-intercept is like the y-intercept). In the form y=mx + b, this is °F = (9/5)°C + 32°.
Practice solving this formula for C to go the other way.
For this problem: F = (9/5)*50 + 32 = 122°
Checking:
To convert from °F back to °C, use C=(5/9)(F-32)
C = (5/9)(122-32) = (5/9)(90) = 50°C