please help!!!

Question

Out of all of the 2010 murder cases, 28.8% killed by family members, 53% by acquaintance and the remainder by stranger. What's probability that a randomly selected murder victim was killed by stranger?

Answer 1

Probability may be expressed as a fraction (e.g.,  1/2), a percent (e.g., 50%) or a decimal (0.50).

 

For events that have the same independent probability (i.e., a uniform distribution), the sum of their probability values is 1 or 100% (i.e., certainty).

 

In this problem, the first two events have probabilities of 28,8% and 53%.  The third (independent) event is the only other possibility (and the sum of the probabilities must be 100%), so it is 18.2% likely to happen.

 

Note: It is not clear whether 2010 was the year or the total number of murder cases, but it doesn't matter (as long as we have enough cases to get a tenth of a percent -- for 28.8% -- to represent the probability).