Stephanie M. answered 06/18/15
Tutor
5.0
(888)
Degree in Math with 5+ Years of Tutoring Experience
Remember that distance = (rate)(time). We'll write two equations: one for Shyam rowing upstream (against the current) and one for Shyam rowing downstream (with the current).
UPSTREAM:
Shyam travels a distance of 36 km. We're not told the rate at which he rows, so call that r. That means he travels upstream (against the current) at a rate of r - 3 kph. Shyam travels a time of 4 hours. So:
36 = (r - 3)(4)
DOWNSTREAM:
Shyam travels an unknown distance d. He travels downstream (with the current) at a rate of r + 3 kph. Shyam travels a time of 6 hours. So:
d = (r + 3)(6)
Now you have a system of equations:
36 = (r - 3)(4)
d = (r + 3)(6)
Simplify the first equation to solve for r:
36 = 4r - 12
48 = 4r
12 = r
Plug that into the second equation to solve for d:
d = (12 + 3)(6)
d = (15)(6)
d = 90
Shyam can travel a distance of d = 90 km downstream in 6 hours.