Find the general solution of (x+1)^2*y"+3(x+1)y'+0.75y=0 that is valid in any interval not including the singular point.
Answer: y=c1*abs(x+1)^(-1/2)+c2*abs(x+1)^(-3/2)
Find the general solution of (x+1)^2*y"+3(x+1)y'+0.75y=0 that is valid in any interval not including the singular point.
Answer: y=c1*abs(x+1)^(-1/2)+c2*abs(x+1)^(-3/2)
This is just one of those polynomial cases. You start by assuming that y is of the form (x+1)^r, calculate y' and y'', plug them back in, factor what you get, and solve the r equation that you get so that the whole thing can be zero. You get more than one value of r, so the general solution is a linear combination of both values.