Arthur D. answered • 05/21/15
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Mathematics Tutor With a Master's Degree In Mathematics
milk to water ratio is 7:5
mixture must be a multiple of 7+5=12; 12,24,36,48,...
9 liters removed
let x=the multiplier to determine the total amount of solution
(7x/12x)*9=63x/12x=63/12=21/4 milk removed (5 1/4 L of milk removed)
(5x/12x)*9=45x/12x=45/12=15/4 water removed (3 3/4 L of water removed)
7x=total amount of milk
5x=total amount of water
7x-21/4=amount of milk left
5x-15/4+9=amount of water you have after taking out 15/4 water and adding 9 L of water
(7x-21/4)/(5x-15/4+9)=7:9 the new ratio of milk to water
simplify
(7x-21/4)/(5x+21/4)=7/9
cross multiply
9(7x-21/4)=7(5x+21/4)
63x-189/4)=35x+147/4
63x-35x=189/4+147/4
28x=336/4
28x=84
x=84/28
x=3
7*3=21 L of milk initially (this is the answer to your question)
5*3=15 L of water initially
initial mixture consisted of 21+15=36 L
Arthur D.
tutor
You're welcome, Amey.
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05/27/15
Amey B.
please sir i have one confusion
if we remove 21/4 and 15/4
so why we dont directly do this then mix 9 water
so 7x-21/4=28x-21 and for water 5x-15/4 = 20x-15 then we add water 20x-15 +9 then water 20x+21
4 4 4 4
will this correct
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05/27/15
Amey B.
please sir check this answer
5 litres of milk taken out from container full of milk then filled with water. Again 5 litre of the mixture is drawn and container filled with water. if the ratio of milk and water now left in the container is 6:9 find the capacity of container
initially milk was x
5 litres of milk taken out so milk = x-5, water =5
Again 5 litre of the mixture is drawn
x-5+x=x so milk = x-5/x*5 then milk taken out 5x-25/x
water = 5/x*5 then water taken out 25/x
remaining milk x-5-5x-25 = x^2-10x-25
x x
remaining water 5-25 =5x-25
x x
x^2-10x-25 =6
5x-25 9
9(x-5)(x-5)=30x-150
18x-30x=-150+90
x=5
is this correct please explain me if it is wrong
5 litres of milk taken out so milk = x-5, water =5
Again 5 litre of the mixture is drawn
x-5+x=x so milk = x-5/x*5 then milk taken out 5x-25/x
water = 5/x*5 then water taken out 25/x
remaining milk x-5-5x-25 = x^2-10x-25
x x
remaining water 5-25 =5x-25
x x
x^2-10x-25 =6
5x-25 9
9(x-5)(x-5)=30x-150
18x-30x=-150+90
x=5
is this correct please explain me if it is wrong
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05/29/15
Amey B.
05/26/15