Twice the sum of two consecutive integers is 10 less than 5 times the smaller integer. Find the greater integer.

Call the smaller consecutive integer X

Then the greater is X+1

The sum of these integers is X+(X+1) = 2X +1

Twice the sum is 2(2X+1) = 4X+2

10 less than 5 times smaller = 5X-10

So 5X-10 = 4X +2

X = 12

Therefore the greater integer X+1 = 13

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