Multiply (2x+4)^2

Whenever you have something of the form (a + b)^2 you wanna apply the identity:

(a + b)^2 = a^2 + 2*a*b + b^2 thus:

(2x + 4)^2 = 4x^2 + 16x + 16

Multiply (2x+4)^2

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Whenever you have something of the form (a + b)^2 you wanna apply the identity:

(a + b)^2 = a^2 + 2*a*b + b^2 thus:

(2x + 4)^2 = 4x^2 + 16x + 16

Hey there. Since you are squaring it, you multiply it by itself. Thus it's:

(2x + 4)(2x + 4)

You need to FOIL it. You know, First, Outside, Inside, Last:

4x^{2} + 8x + 8x + 16.

Then combine like terms:

4x^{2} + 16x + 16.

Shake a leg.

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