
Charles K. answered 09/08/19
Retired College Professor Working With Students At All Levels
A total of 586 people attended a banquet. A total of $9,423.70 in revenue was collected. Student tickets cost $12.95 and Adult tickets cost $17.95. Find the number of student and adult tickets sold.
Let: Student tickets = S
Let: Adult tickets = A
Given: Student ticket prices = $12.95
Given: Adult ticket prices = $17.95
Given: Total tickets sold = 586
Given: Total revenue = $9,423.70
S + A = 586 (1)
12.95 S + 17.95 A = 9,423.70 (2)
Multiply equation (1) by –12.95
–12.95 S – 12.95 A = –12.95 (586)
12.95 S + 17.95 A = 9,423.70
–12.95 S – 12.95 A = –7,588.70
12.95 S + 17.95 A = 9,423.70
Add the two equations together. The S variables will drop out. That will leave us with A variables only. We then solve for A and substitute and solve for S.
5A = 1,835
Divide through by 5
A = 367 Adult tickets sold
Now substitute 367 for A and solve for S.
S + A = 586
S + 367 = 586
S = 219 Student tickets sold
Check 1
S + A = 586
219 + 367 = 586
586 = 586 Check
Check 2
12.95 S + 17.95 A = 9,423.70
12.95 (219) + 17.95 (367) = 9,423.70
2,836.05 + 6,587.65 = 9,423.70
9,423.70 = 9,423.70 Check
The final answer is, there were 219 Student tickets sold and 367 Adult tickets sold.
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