Arthur D. answered 05/12/15
Tutor
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Forty Year Educator: Classroom, Summer School, Substitute, Tutor
the largest is 40
all are even
one is divisible by 7
even and divisible by 7 gives you only 2 possibilities, 14 and 28
the sum is 44
44-28=16
16=12+4
4 and 12 are divisible by 4
28 is divisible by 7
4, 12, and 28 are all even
4+12+28=44
4, 12, and 28 are the numbers (the other possibility, 14, doesn't work: 44-14=30 and 30 can't be expressed as the sum of 2 multiples of 4 because 30 is not a multiple of 4; if you add 2 multiples of 4 you must get another multiple of 4) (notice that 16 is a multiple of 4)