Stephanie M. answered 05/07/15
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This is an application of Boyle's Law:
P1V1 = P2V2
Initial pressure P1 = 1 atmosphere, since you've been told it's STP (standard temperature and pressure). Initial volume is unknown. Final pressure P2 = 16, and final volume V2 = 1 × 107. Plug in the values and solve for the unknown, V1.
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Hi Teresa,
Here's a more thorough explanation. This problem uses a formula called Boyle's Law, which says that if you've got a gas in some contained area, then (as long as you don't change the gas's temperature or add more gas to the contained area) volume and pressure are related. Let's say you make some change to the gas's pressure or volume without changing anything else. The gas initially had pressure P1 and volume V1. After the change, it has final pressure P2, and final volume V2. Knowing any three of those values, you can find the other one using Boyle's Law:
P1V1 = P2V2
This problem is one of those situations. We're not changing number of molecules or temperature, just volume and pressure. Initially, the gas is at the surface at STP, which is "Standard Temperature and Pressure." Standard pressure is 1 atmosphere, so P1 = 1. Initially, we don't know the volume V1. That's what the problem asks you to find. After the gas is brought down to the underwater environment, pressure is 16 atmospheres, so P2 = 16. Volume in the environment is 107 liters (I assume you meant for that to be an exponent), so V2 = 107. Plug those values into Boyle's Law:
P1V1 = P2V2
(1)V1 = (16)(107)
V1 = 16 × 107
V1 = 1.6 × 108 (proper scientific notation)
So, the initial volume of gas you need is 1.6 × 108 L.
Does that make sense?
Teresa H.
05/07/15