Nathan B. answered 05/01/15
Tutor
5
(20)
Elementary and Algebraic skilled
x2 + 3x + 1
----------------------
x+2|x3 + 5x2 + ax + 2
-x3 - 2x2
------------
3x2 + ax
-3x2 - 6x
-----------
ax-6x+2
-x -2
-----------
0
We need to have x = 1 in this last bit:
a - 6 = 1
a = 7
Checking:
(x + 2)(x2 + 3x + 1)
x3 + 3x2 + x + 2x2 + 6x + 2
Combine like terms:
x3 + 5x2 + 7x + 2, which is our original expression.
so 'a' must be 7.