
Mark M. answered 04/28/15
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Mathematics Teacher - NCLB Highly Qualified
Y0/3 = Y0e-ln2(1/5700)t
Y0/3 = Y0e-0.00012t
1/3 = e-0.00012t
ln(1/3) = ln e-0.00012t
-1.09862 ≈ -0.00012t
9155.18 ≈ t