Isaac C. answered 04/29/15
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Since the radius of its (almost) circular orbit is 5.79 x 1010m, then mercury travels 2*pi* 5.79 x 1010m during a single orbit.
T = distance/speed = 2*pi* 5.79 x 1010m/ (4.78*104 m/s). = 7.61 *106s or 0.241 years.