A company's monthly cost (c) in dollars for storing x units of a product isc = 2000 + 1.65x.

Question

A company's monthly cost (c) in dollars for storing x units of a product isc = 2000 + 1.65x. What is the largest number of units that can be stored so that the monthly cost does not exceed $3600?

 

need steps

Answer 1

Hi Susan.

 

So you want your monthly cost to stay under $3600, right? And the cost = 2000 + 1.65 x (number of units stored).

 

This is a fairly straightforward problem. To get started, you should structure it as:

 

[Cost Limit] >= [Actual Cost]

3600 >= 2000 + 1.65 x

 

Solving this equation should be pretty simple for you, as you apparently know how to use a computer! :)

 

3600 - 2000 >= (2000 - 2000) + 1.65 x  [subtract 2000 from each side]

1600 >= 1.65 x

(1600/1.65) >= x    [divide each side by 1.65]

969.7 >= x

 

So the largest number of units that can be stored should be 969... unless I've made a horrible error, which is always a possibility.