Chemistry help

Question

022 (part 1 of 2) 10.0 points

The double-replacement reaction between silver

nitrate and sodium bromide produces silver

bromide, a component of photographic

film. If 6 mol of silver nitrate reacts, what

mass of sodium bromide is required?

Answer in units of g.

023 (part 2 of 2) 10.0 points

What mass of silver bromide is formed?

Answer in units of g.

Answer 1

1. The equation for the reaction is:

 

AgNO₃ + NaBr ---> AgBr + NaNO₃

 

So for each mol of silver nitrate, you need 1 mol of sodium bromide.  That means you need a total of 6 mols of sodium bromide.  We just have to figure out the molecular mass of sodium bromide:

 

Na: 22.99

Br: 79.90

 

Total is 102.89, so 6 mols of NaBr has a mass of 6 * 102.89 = 617.34 g.

 

2. Again, for each mol of sliver nitrate, you get 1 mol of silver bromide.  We have to figure out the molecular mass of silver bromide:

 

Ag: 107.87

Br: 79.90

 

Total is 187.77.  So with 6 mols of AgBr, the mass will be 1126.62 g.