x and y int for 2+x/16-x^2

Question

I found the asymptotes. Having problems with the x and y int.

Answer 1

f(x) = (2 + x) / (16 - x²)

 

 

To find the x-intercept, set f(x) equal to zero.  This means that we set the numerator to zero.

 

To find y-intercept, evaluate f(0).  This means evaluate f(x) when x=0.